(x+3)^=7x+29

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Solution for (x+3)^=7x+29 equation: 



(x+3)^=7x+29

We move all terms to the left:

(x+3)^-(7x+29)=0

We get rid of parentheses

(x+3)^-7x-29=0

We add all the numbers together, and all the variables

-7x+(x+3)^-29=0

We move all terms containing x to the left, all other terms to the right

-7x+(x+3)^=29

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